Show results according to percent using if statement in c language

Show results according to percent using if statement in c language 

#include<stdio.h>

int main()

{

  

float p;

  

printf("ENTER THE MARKS\n");

  

scanf("%f",&p);

  

if(p<=100&&p>=60)

  

{

    

printf("FIRST DIVISION");

  

}

  

if(p<=60&&p>=45)

  

{

   

printf("SECOND DIVISION");

  

}

  

if(p<=45&&p>=33)

  

{

   

printf("THIRD DIVISION");

  

}

  

if(p<=33)

  

{

    

printf("FAIL");

  

}

}